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8*8LED点阵显示0-9

作者:时间:2016-11-29来源:网络收藏
电路很简单8*8点阵的行和列分别接在单片机的p3口和p1口,我测试成功.
#include unsigned char code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};unsigned char code digittab[10][8]={       {0x00,0x00,0x3e,0x41,0x41,0x41,0x3e,0x00},     //0{0x00,0x00,0x00,0x00,0x21,0x7f,0x01,0x00},     //1{0x00,0x00,0x27,0x45,0x45,0x45,0x39,0x00},    //2{0x00,0x00,0x22,0x49,0x49,0x49,0x36,0x00},    //3{0x00,0x00,0x0c,0x14,0x24,0x7f,0x04,0x00},     //4{0x00,0x00,0x72,0x51,0x51,0x51,0x4e,0x00},    //5{0x00,0x00,0x3e,0x49,0x49,0x49,0x26,0x00},    //6{0x00,0x00,0x40,0x40,0x40,0x4f,0x70,0x00},     //7{0x00,0x00,0x36,0x49,0x49,0x49,0x36,0x00},    //8{0x00,0x00,0x32,0x49,0x49,0x49,0x3e,0x00}     //9};unsigned int timecount;unsigned char cnta;unsigned char cntb;void main(void){TMOD=0x01;TH0=(65536-3000)/256;TL0=(65536-3000)%256;TR0=1;ET0=1;EA=1;while(1){;}}void t0(void) interrupt 1 using 0{TH0=(65536-3000)/256;TL0=(65536-3000)%256;P3=tab[cnta];P1=digittab[cntb][cnta];cnta++;if(cnta==8){cnta=0;}timecount++;if(timecount==333){timecount=0;cntb++;if(cntb==10){cntb=0;}}}


关键词: 8*8LED点阵显示0-

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