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ADC0809AD转换器基本应用技术

作者:时间:2013-04-02来源:网络收藏

T0X: NOP

MOV TH0,#(65536-4000)/256

MOV TL0,#(65536-4000) MOD 256

MOV DPTR,#DPCD

MOV A,DPCNT

ADD A,#DPBUF

MOV R0,A

MOV A,@R0

MOVC A,@A+DPTR

MOV P1,A

MOV DPTR,#DPBT

MOV A,DPCNT

MOVC A,@A+DPTR

MOV P2,A

INC DPCNT

MOV A,DPCNT

CJNE A,#8,NEXT

MOV DPCNT,#00H

NEXT: RETI

DPCD: DB 3FH,06H,5BH,4FH,66H

DB 6DH,7DH,07H,7FH,6FH,00H

DPBT: DB 0FEH,0FDH,0FBH,0F7H

DB 0EFH,0DFH,0BFH,07FH

END

8. C语言源程序

#include AT89X52.H>

unsigned char code dispbitcode[]={0xfe,0xfd,0xfb,0xf7,

 0xef,0xdf,0xbf,0x7f};

unsigned char code dispcode[]={0x3f,0x06,0x5b,0x4f,0x66,

0x6d,0x7d,0x07,0x7f,0x6f,0x00};

unsigned char dispbuf[8]={10,10,10,10,10,0,0,0};

unsigned char dispcount;

sbit ST=P3^0;

sbit OE=P3^1;

sbit EOC=P3^2;

unsigned char channel=0xbc;//IN3

unsigned char getdata;

void main(void)

{

TMOD=0x01;

TH0=(65536-4000)/256;

TL0=(65536-4000)%256;

TR0=1;

ET0=1;

EA=1;

P3=channel;

while(1)

{

ST=0;

ST=1;

ST=0;

while(EOC==0);

OE=1;

getdata=P0;

OE=0;

dispbuf[2]=getdata/100;

getdata=getdata%10;

dispbuf[1]=getdata/10;

dispbuf[0]=getdata%10;

}

}

void t0(void) interrupt 1 using 0

{

TH0=(65536-4000)/256;

TL0=(65536-4000)%256;

P1=dispcode[dispbuf[dispcount]];

P2=dispbitcode[dispcount];

dispcount++;

if(dispcount==8)

{

dispcount=0;

}

}


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